Jan 27, 2026
## Chapter 13: Algorithmic Mathematics (Big-O Intuition) — “will this finish today?”
Big-O in the simplest way:
Big-O means:
“When input gets bigger, how fast will time grow?”
That’s it.
### First, set the meaning of n
In Big-O, we use `n` as:
- number of items in array
- number of users in a list
- number of rows in a file
- number of nodes in a graph
So when I say “n becomes big”, I mean: your input becomes big.
### The biggest confusion (students always do this)
Students want Big-O to tell exact seconds.
Like:
“O(n) means 2 seconds.”
No.
Big-O is not a stopwatch.
Big-O is a growth style.
Like:
- grows like a straight line
- grows like a square
- grows like doubling and doubling
### Why we ignore small details
If your work is:
```text
3n + 100
```
For big n, the `+100` does not matter much.
So we say it is like `n`.
If your work is:
```text
n^2 + 10n + 50
```
For big n, `n^2` becomes the boss.
So we say it is like `n^2`.
This is why Big-O looks “simplified”.
### The Big-O “feeling” list (remember this like a shortcut)
- O(1): same time even if n grows (almost same)
- O(n): grows like one full scan
- O(n^2): grows like “every pair with every pair”
- O(log n): grows like “keep cutting in half”
- O(n log n): common in good sorting
- O(2^n): grows like “all subsets / all choices” (very dangerous)
### Time vs memory (quick)
- **Time** = how many steps your program has to do.
More steps = more waiting.
- **Space (memory)** = how much extra storage your program uses while working.
Think like this:
- If you don’t store anything extra, you may have to re-check the same things again and again (time goes up).
- If you store some extra data (a map, set, cache), you can answer faster (time goes down), but memory goes up.
Simple real-life example:
- Want to know if a number is already seen?
If you keep a `set` of seen numbers, checking is fast, but you use memory for the set.
- If you don’t keep a set, you may scan the list every time. That saves memory, but wastes time.
#### One loop (O(n))
Imagine you have a list of `n` numbers and you want the biggest one.
How do you do it? You do the normal thing:
- start with “current biggest”
- look at each number one by one
- update “current biggest” if you find a bigger number
Important part: you look at each item once.
So the work is like:
- `n` items → `n` looks
That’s why it is **O(n)**.
If your list becomes twice bigger, you will do roughly twice looks. That’s the whole meaning.
#### Two loops: add vs multiply
Many beginners get confused here, so here is a daily-life way to see it.
##### Case A: two loops one after another (add)
```text
loop n
loop n
```
Here you do one full scan, then another full scan.
Total work:
```text
n + n = 2n
```
In Big-O we drop the 2, so it is still **O(n)**.
##### Case B: one loop inside another (multiply)
```text
loop n:
loop n:
```
Here, for every 1 item in the outer loop, you again scan `n` items inside.
So total work is:
```text
n * n = n^2
```
That’s **O(n^2)**.
A human picture:
- You have `n` students.
- You want to check every pair of students (who can talk to who).
- For each student, you check with all students.
That becomes “pair with pair”, so it grows like n².
Easy rule:
- separate loops add
- nested loops multiply
#### Why O(n^2) looks okay in small test, then breaks later
If n = 1,000:
- n^2 = 1,000,000 (still maybe okay)
If n = 100,000:
- n^2 = 10,000,000,000 (very heavy)
So the same code can feel fast today, and dead tomorrow.
#### Cutting in half (O(log n)) = binary search idea
Binary search does this:
- remove half the array each step
So steps are like:
```text
n → n/2 → n/4 → n/8 → ...
```
How many times can you do this until it becomes 1?
That count is `log n`.
So binary search is O(log n).
This is why it feels super fast.
#### Sorting (O(n log n)) = fast and practical
Good sorting (merge sort / quicksort average) is around O(n log n).
It is slower than O(n), but much better than O(n^2).
That’s why sorting is a “power move” in many problems.
#### Exponential (O(2^n)) = the real enemy
If you try “all subsets” of n items, count becomes:
```text
2^n
```
For n = 30, it is already huge.
This is why:
- naive Fibonacci recursion is slow
- subset brute force dies fast
When you see 2^n, your first thought should be:
“Can I avoid trying everything?”
---
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## Conclusion
In this article, we explored the core concepts of All about Computer Mathematics - Algorithmic Mathematics (Big-O Intuition) — “will this finish today?”. Understanding these fundamentals is crucial for any developer looking to master this topic.
## Frequently Asked Questions (FAQs)
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