Jan 27, 2026
## Chapter 7: Combinatorics — counting without brute force (so you don’t melt your CPU)
A very common new-programmer pain:
You write a solution and it works… but it’s slow.
Then you try to speed it up and you realize something scary:
Sometimes the problem is not your code style.
Sometimes the problem is the *number of possibilities*.
This is where combinatorics shows up. It’s basically counting, but in a “save your time” way.
People often mix up these two questions:
- “How many different options exist?”
- “How fast can my program try them?”
Those are connected, but not the same.
If there are 10 possibilities, even slow code is fine.
If there are 10^12 possibilities, even fast code cries.
So we learn counting to estimate the size of the search space *before* writing a brute-force algorithm.
### The core idea (no drama)
If a task happens in steps, and:
- step 1 has A choices
- step 2 has B choices
- step 3 has C choices
then total choices = A × B × C.
That’s the “multiplication principle”.
It’s the math version of nested loops.
### Permutation vs combination (the only difference you must remember)
This is where beginners trip. It’s not hard, it’s just easy to mix up:
- Permutation: order matters
“AB” and “BA” are different
- Combination: order does not matter
{A,B} is the same as {B,A}
When order matters, the count becomes much bigger.
#### Basic: nested loops are counting machines
Suppose you have:
- 3 shirt colors
- 2 pant colors
- 4 shoe choices
How many outfits?
You don’t need to list them.
It’s:
3 × 2 × 4 = 24
In code, this is the same logic as:
- loop shirts (3)
- loop pants (2)
- loop shoes (4)
The total iterations are multiplied, not added.
#### Common mistake: adding instead of multiplying
In a hurry, people sometimes do this:
“I have 10 digits and 26 letters, so that’s 36 passwords.”
Nope. That’s not how passwords work.
If your password is 2 characters long and each character can be:
- 10 digits OR 26 letters = 36 choices per character
Then total passwords are:
36 × 36 = 36^2 = 1296
The moment you do “two steps”, you multiply.
This looks small for length 2. Now imagine length 12.
That’s why password cracking is about counting first, not guessing first.
#### Simple reason: why “order matters” changes everything
You have 3 apps: A, B, C.
Question 1: “Choose 2 apps to install.”
This is a combination. Order does not matter.
Possible sets:
- {A,B}
- {A,C}
- {B,C}
Total: 3
Question 2: “Arrange 2 apps on the home screen (left to right).”
Now order matters. This is a permutation.
Possible arrangements:
- AB, BA
- AC, CA
- BC, CB
Total: 6
Same “two items” idea, but order doubled the count.
That’s why in algorithms you must be clear:
- Are you selecting items? (combination)
- Or ordering them? (permutation)
Mixing this up creates wrong answers and wrong complexity estimates.
#### Practical: counting passwords (and why “8 characters” can still be weak)
Let’s say a password uses only lowercase letters (26 options each).
Length 8 means:
26^8 possibilities
That number is huge already.
Now students hear this and relax too early. But a real system matters:
- if users choose “aaaaaaaa” or “password”
- if there are leaked password lists
- if the attacker doesn’t brute force, but uses smarter guesses
So counting tells you the *upper bound* of the search space.
Human behavior often makes the real space much smaller.
Still, combinatorics gives you the first reality check:
“Is brute force even possible?”
#### Practical + very CS-useful: number of subsets is 2^n (bitmask thinking)
Suppose you have n features in an app, and each feature can be:
- ON
- OFF
How many configurations exist?
Each feature is a 2-choice step, repeated n times:
2 × 2 × ... × 2 (n times) = 2^n
This is also the number of subsets of a set with n elements.
And this is exactly why bitmasks are so popular:
- each bit is ON/OFF
- a bit pattern represents one subset
So when you see an algorithm that checks “all subsets”, your brain should scream:
2^n grows fast. Be careful.
#### Extra tip: pigeonhole principle (hash collisions without heavy math)
This principle sounds childish, but it explains real computer bugs.
Pigeonhole idea:
If you have more items than boxes, at least one box gets 2 items.
Now translate to hashing:
- items = different inputs (strings, files, passwords)
- boxes = hash outputs
If a hash function outputs 32-bit values, there are 2^32 possible hashes.
If you try more than 2^32 different inputs, a collision must happen somewhere.
Not “maybe”. Must.
Even before that limit, collisions can happen. The guarantee just becomes absolute after the count crosses the number of boxes.
This is the counting version of “you can’t store infinite unique things in a finite space”.
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## Conclusion
In this article, we explored the core concepts of All about Computer Mathematics - Combinatorics — counting without brute force (so you don’t melt your CPU). Understanding these fundamentals is crucial for any developer looking to master this topic.
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